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Thermodynamics is the study of relationships between heat and other energy forms, thus relating all energy forms with one another. For Chemical Engineers, Thermodynamics encompasses many areas, from reaction kinetics to phase equilibria, with many mathematical relationships that can describe these. This lesson will give an example of a derivation for one such equation you may encounter in studying Thermodynamics.

Clausius-Clapeyron Equation Derivation

The previous lesson introduced the concept of Gibbs Free Energy, G, and its relationship to temperature, pressure, volume, enthalpy, and entropy. Applying this to 2 phases in equilibrium (i.e. where G = 0), yields the analysis shown in Equation 1.

\(dG(g) = dG(l) \therefore V(g)DP - S(g)dT = V(l)dP - S(l)dT\)

\(\frac{dP}{dT} = \frac{S(g) - S(l)}{V(g)-V(l)}\)

\(\frac{dP}{dT} = \frac{\Delta S_v}{\Delta V_v}\)

\(\text{As} \: \Delta G= 0 \: \text{and} \: \Delta G = \Delta H - T \Delta S\)

\(\Delta S_v = \frac{\Delta H_v}{T}\)

\(\therefore \frac{dP}{dT} = \frac{\Delta H_v}{T \Delta V_v}\)

Equation 1. Derivation of the Exact Clapeyron Equation, where \(d\) indicates a derivative, \(G\) is the Gibbs Free Energy, \(V\) is the volume, \(T\) is the temperature, \(P\) is pressure,\(H\) is enthalpy, \(S\) is entropy, \(l\) and \(g\) represent values in the liquid and gaseous phases respectively, and the \(v\) subscript indicates the vapour state.

This first derivation gives us the Exact Clapeyron equation. Given a Pressure-Temperature phase diagram graph, this can be used to give the gradient of tangents to the curve which separates two phases, shown in Figure 1.

Figure 1. A Generic Pressure-Temperature Phase diagram, where the Clapeyron Equation would give the slope of tangents to the curves shown.

The Clausius-Clapeyron equation can be used when the vapour involved behaves perfectly, thus following the ideal gas law. The derivation of this relationship is shown in Equation 2. This is frequently used to calculate the vapor pressure of a liquid, which is the point at which a substance can exist in all three phases.

\(\text{Assume}\: \Delta V_v \simeq V(g) \therefore V(g) = \frac{RT}{P}\)

\(\frac{dP}{dT} = \frac{\Delta H_v}{RT^2} P\)

\(\text{Thus} \: \frac{dlnP}{dT} = \frac{\Delta H_V}{RT^2}\)

Equation 2. Derivation of the Clausius-Clapeyron Equation based on the assumption that the vapour behaves as an ideal gas. \(V\) is the volume of substance, \(T\) is the temperature, \(P\) is the pressure, \(H\) is the enthalpy and the \(v\) subscript indicates the vapour phase.

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